CoursesAIMathCodePhysicsAbout and FAQ

TwiddleLab / Math / Growth: Exponents and Logs

Faster and Faster: the Number e

Lesson 10 of 11 · 7 min · Free, no account needed

What you will learn

  • Compound interest pays interest on interest: 50% twice turns $1 into $2.25, not $2.
  • Splitting 100% into n payments gives (1 + 1/n)ⁿ, which approaches e ≈ 2.71828.
  • Growth paid continuously is e^(rt). Its inverse is the natural log ln: ln 2 ≈ 0.69, so 6.9% doubles in 10 years.

Start the lesson

How the lesson goes

  1. A bank pays 100% a year. Would you rather get it once, or 1% a hundred times?

    Once turns $1 into $2. Bet what 1% a hundred times gives.

  2. Start small: two payments of 50%.

    Pay the interest twice and watch the stack.

  3. Split the 100% into more and more payments.

    Turn the dial from once a year to every second.

  4. The ceiling is a number: e.

    (1 + 1/n)ⁿ grows with n but never passes e ≈ 2.71828.

    Growth paid continuously at rate r for time t multiplies by e^(rt).

    The inverse of eˣ is the natural log, ln x: ln e = 1, ln 2 ≈ 0.693.

  5. Make $1 double in exactly 10 years.

    The bank pays continuously, so $1 becomes e^(rt). Turn the rate until it lands on $2.

    Doubling means e^(10r) = 2. The natural log undoes e: 10r = ln 2 ≈ 0.693, so r ≈ 6.9%. That is where the rule of 70 comes from: 70 / rate ≈ years to double.

  6. Game: beat the bank.

    Four rounds. Tap the bank that turns $1,000 into more in one year.

  7. AI uses e in the sigmoid.

    The sigmoid 1 / (1 + e^(−x)) squeezes any number into 0 to 1. Drag the point until the output is 0.9.

    1/(1 + e^(−x)) = 0.9 when e^(−x) = 1/9, so x = ln 9 ≈ 2.2.

  8. $1,000 at 100% a year, paid continuously. How much after one year?

    Paying 100% continuously multiplies by e^(1 × 1) = e ≈ 2.71828, so $1,000 becomes about $2,718.28.

  9. One more thing that makes e special.

    Tap a curve to see its tangent at x = 0. Which one has slope exactly 1? Then Check.

    The slope of bˣ at 0 is ln b: ln 2 ≈ 0.69, ln 3 ≈ 1.10, and ln e = 1. That is why e is the natural base.

Previous lesson: Log Scales · Next lesson: Project: Will It Go Viral? · Part of the course: Growth: Exponents and Logs

Lessons are interactive and need JavaScript. Turn it on to play them.

Loading TwiddleLab